Gibbs energy of formation of UPd3(s)
Source abstract
Abstract
Abstract Gibbs energy of formation of UPd 3 (s) has been determined by measuring the equilibrium CO(g) pressure over {UO 2 (s) + C(s) + UPd 3 (s) + UPd 4 (s)} and is given as Δ f G 0 m ( UPd 3 , s ,T) kJ mol −1 ±4.1=−526.9+0.1259 T (K) , (1175⩽T (K) ⩽1333). Using the required literature data, Δ f H 0 m (UPd 3 , s, 298.15 K) has been calculated as −(502.3 ± 5.1) kJ mol −1 .
Source: openaire · Quality: candidate unverified · Source record ↗
Research context
OpenAlex topics: Radioactive element chemistry and processing · Nuclear Materials and Properties · Rare-earth and actinide compounds
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References (11)
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